1.7 Graphing Shortcuts

 

The graph of an equation in x and y is the set of all points with coordinates (x,y) satisfying the equation.  In the case of a function y = f ( x ), the graph of f is the point set { (x,y) | y = f ( x ) }.

 

The most fundamental way to sketch the graph of a function is to

 

(1)  Select an interval on the x-axis encompassing all or part of the domain of the function

(2)  Select a finite set of points in the domain of the function lying in that selected interval 

(3)  For each of the selected values of x, the corresponding value of y is computed using the formula for

y = f ( x ). 

(4) Plot this finite set of points in the x y plane and sketch the graph by connecting the points, being careful not to connect two adjacent points unless all the input values lying between the two points are in the domain of the function.

 

However there are certain shortcuts which may make the task of sketching graphs easier by reducing the number of points which must be plotted.  These shortcuts may be denoted as

 

(1) symmetry

(2) shifting, i.e. translation

(3) stretching or shrinking

(4) reflecting

 

These shortcuts apply not only to the graphs of functions (vertical line test) but to all graphs having an x y equation.

 

Symmetry

 

A graph is symmetric with respect to the y-axis if the point ( - x, y ) is on the graph whenever the point

( x, y ) is on the graph.  This means that if one replaces every occurrence of x in the equation with ( - x ) [be sure to put parentheses around the - x] and then simplifies the equation, the resulting equation will be equivalent to the original equation.

 

Exercise 1.7.1 

 

Let  on the interval [ - 3, 3 ].  Replace the x in the equation with ( - x ) and simplify.  Did you get the same equation?  Sketch the graph and notice that for every point ( x, y ) on the graph, the mirror image of that point in the y axis, namely the point ( - x, y ), is also on the graph.

 

Solution

 

A function which is symmetric with respect to the y-axis is called an even function and has the special property that f ( - x ) = f ( x ) for every x in the domain of the function.

 

Exercise 1.7.2

 

Show that the function  is an even function.

 

Solution

 

A graph is symmetric with respect to the x-axis if the point ( x, - y ) is on the graph whenever the point

( x, y ) is on the graph.  This means that if one replaces every occurrence of y in the equation with ( - y ) [be sure to put parentheses around the - y] and then simplifies the equation, the resulting equation will be equivalent to the original equation.  Note that if y is not 0 then ( x, y ) and ( x, - y ) are two points which lie on the same vertical line, so the graph would not be the graph of a function in that case. [Why not?]

 

Exercise 1.7.3

 

Let  for y in the interval [ - 2, 2 ].    Replace the y in the equation with ( - y ) and simplify.  Did you get the same equation?  Sketch the graph and notice that for every point ( x, y ) on the graph, the mirror image of that point in the x axis, namely the point ( x, - y ), is also on the graph.

 

Solution

 

A graph is symmetric with respect to the origin if the point ( - x,  - y ) is on the graph whenever the point

( x, y ) is on the graph.  This means that if one replaces every occurance of x in the equation with ( - x ) and every occurance of y in the equation with ( - y ) [be sure to put parentheses around the - x and - y] and then simplifies the equation, the resulting equation will be equivalent to the original equation.  Notice that the point ( - x,  - y )  is the same distance from the origin as the point ( x, y ) , except it is on the opposite side of the origin.

 

Exercise 1.7.4

 

Let  for x in the interval [ - 2, 2 ]. Replace the x in the equation with ( - x ) and replace the y in the equation with ( - y ) and simplify.  Did you get the same equation?  Sketch the graph and notice that for every point ( x, y ) on the graph, the point ( - x, - y ), is also on the graph.

 

Solution

 

A function which is symmetric with respect to the origin  is called an odd function and has the special property that f ( - x ) = - f ( x ) for every x in the domain of the function.

 

Exercise 1.7.5 

 

Show that the function  is an odd function.

 

Solution

 

By noticing the symmetry of a graph, one need plot only half as many points, obtaining the other points of the graph by symmetry.

 

Translation

 

The horizontal translation principle states that replacing each occurrence of x in an x y equation with

 ( x - h ) [be sure to put parentheses around the x - h ] produces an equation whose graph lies h units horizontally from the graph of the original equation.  The h can be any real number.

 

Exercise 1.7.6

 

Sketch the graph of ,  and .  Notice the application of the horizontal translation principle

 

Solution

 

Stated in terms of function notation,  the horizontal translation principle states that the graph of 

y = f ( x - h ) is shifted h units horizontally from the graph of y = f ( x ).  Thus the graph of y = f ( x - 2 ) will lie two units to the right of the graph of y = f ( x ) and the graph of y = f ( x + 3 ) = f ( x - ( - 3 ) ) will lie three units to the left of y = f ( x ).  

 

Exercise 1.7.7

 

Sketch the graph of .  Then sketch the graphs of  and .

 

Solution

 

The vertical translation principle states that replacing each occurrence of y in an x y equation with ( y - k ) [be sure to put parentheses around the y - k ] produces an equation whose graph lies k units vertically from the graph of the original equation.  The k can be any real number.

 

Exercise 1.7.8

 

Sketch the graph of ,  and .  Notice the application of the vertical translation principle

 

Solution

 

Stated in terms of function notation,  the horizontal translation principle states that the graph of 

y - k = f ( x  ) [alternately, y = f ( x ) + k ] is shifted k units vertically from the graph of y = f ( x ).  Thus the graph of y - 2 = f ( x  ) will lie two units above the graph of y = f ( x ) and the graph of y + 3= f ( x  ) will lie three units below y = f ( x ).  

 

Exercise 1.7.9

 

Sketch the graph of .Then sketch the graphs of  and .

 

Solution

 

Both the horizontal and vertical translation principles may be applied to the same problem.

 

Exercise 1.7.10

 

Sketch the graph of  using both the horizontal and vertical translation principles.

 

Solution

 

Stretching/shrinking

 

The horizontal stretching/shrinking principle states that replacing each occurrence of x in an x y equation with  x / c stretches the graph horizontally by a factor of c when c > 1 and shrinks the graph horizontally by a factor c when 0 < c < 1.

 

Exercise 1.7.11

 

Sketch the graph of   together with the graph of.  Notice that the first graph is twice as wide as the second.

 

Solution

 

Exercise 1.7.12

 

Sketch the graph of  together with the graph of .  Notice that the first graph is only one-half as wide as the second.

 

Solution

 

The vertical stretching/shrinking principle states that replacing each occurrence of y in an x y equation with  y / c stretches the graph vertically by a factor of c when c > 1 and shrinks the graph vertically by a factor c when 0 < c < 1.

 

Exercise 1.7.13

Sketch the graph of   together with the graph of .  Notice that the first graph is twice as tall as the second.

 

Solution

 

Exercise 1.7.14

 

Sketch the graph of  together with the graph of .  Hint:  Compare this problem to exercise 1.7.12.

 

Exercise 1.7.15

Sketch the graph of   [that is, ], together with the graph of .  Notice that the first graph is only one-half as tall as the second.

 

Solution

 

Exercise 1.7.16

 

Sketch the graph of  together with the graph of .  Hint:  Compare to exercise 1.7.15.

 

Reflection

 

The vertical reflection principle states that replacing each occurrence of x in an x y equation with ( - x )[be sure to put parentheses around the  - x ] reflects the graph of the original equation about the y-axis.

 

Exercise 1.7.17

 

Sketch the graphs of   and .

 

Solution

 

The horizontal  reflection principle states that replacing each occurrence of y in an x y equation with

 ( - y )[be sure to put parentheses around the - y ] reflects the graph of the original equation about the x-axis.

 

Exercise 1.7.18

 

Sketch the graphs of and , i.e. .

 

Solution

 

Exercise 1.7.19

 

Sketch the graph of  using the principles of reflection and translation.

 

Solution

 

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